S114 FORTRAN example for reading ASCII-Files

	program s114_data
c ----------------------------------------------

	implicit none

	INTEGER Z(100)
	INTEGER ZB,ZB3,ENUM
	INTEGER ZB_12,ZB3_12,DZB3,NAL
	INTEGER NZB,NZB3
	INTEGER IENUM,I,INDEX
	CHARACTER*80 ifilen
	LOGICAL BINAC,BINCON

c open file
	write (*,*) ' Enter filename :'
	read (*,*) ifilen
	open(unit=3,file=ifilen,status='old')
	IENUM = 0

c start loop over events
1	CONTINUE
cc reset variables
	BINCON = .false.
	BINAC = .false.
	BORDER = .false.
	do I=1,100
	 Z(I) = 0
	enddo
	ZB_12 = 0
	ZB3_12 = 0
	INDEX=0

cc read event
	read(3,2000,end=1000) ENUM,Z(1),Z(2),Z(3),Z(4),Z(5),
     +    Z(6),Z(7),Z(8),Z(9),Z(10),Z(11),Z(12),ZB,ZB3
	IENUM = IENUM + 1

cc calculate ZB_12,ZB3_12
	do I=1,12
	 if (Z(I).ge.2) ZB_12 = ZB_12 + Z(I)
	 if (Z(I).ge.3) ZB3_12 = ZB3_12 + Z(I)
	 if (Z(I).ne.0) INDEX=I
	enddo

cc determination of Z13,... for events with more than 12 fragments 
	if (INDEX.lt.12) then
	 if ((ZB_12.ne.ZB).or.(ZB3_12).ne.(ZB3)) BINCON = .true.
	else
	DZB3 = ZB3-ZB3_12
	if (DZB3.ne.0) then
ccc IMF's
	  WRITE (*,*) 'IMF-RECONSTRUCTION FOR EVENT :',ENUM,' DZB3=',DZB3
	  IF (DZB3.eq.3) then
	    if (Z(12).lt.3) BINCON= .true.
	    Z(13) = 3
	    INDEX = 13
	  ELSEIF (DZB3.eq.4) then
	    if (Z(12).lt.4) BINCON= .true.
	    Z(13) = 4
	    INDEX = 13
	  ELSEIF (DZB3.eq.5) then
	    if (Z(12).lt.5) BINCON= .true.
	    Z(13) = 5
	    INDEX = 13
          ELSEIF (DZB3.eq.6) then
	    IF (Z(12).ge.6) BINAC = .true.
	    if (Z(12).lt.3) BINCON= .true.
            Z(13) = 3
            Z(14) = 3
            INDEX = 14
          ELSEIF (DZB3.eq.7) then 
	    IF (Z(12).ge.7) BINAC = .true.
	    if (Z(12).lt.4) BINCON= .true.
	    Z(13) = 4
	    Z(14) = 3
	    INDEX = 14
	  ELSEIF (DZB3.eq.8) then
	    IF (Z(12).ge.5) BINAC = .true.
	    if (Z(12).lt.4) BINCON= .true.
	    Z(13) = 4
	    Z(14) = 4
	    INDEX = 14
	  ELSEIF (DZB3.eq.9) then
	    IF (Z(12).ge.5) BINAC = .true.
	    if (Z(12).lt.3) BINCON= .true.
	    Z(13) = 3
	    Z(14) = 3
	    Z(15) = 3
	    INDEX = 15
	  ELSEIF (DZB3.gt.9) then
	    BINAC = .true.
	  ENDIF
	ENDIF
ccc Alpha-particles
	NAL = (ZB - ZB_12 - DZB3)/2
	do i=1,NAL
	 INDEX=INDEX+1
	 Z(INDEX) = 2
	enddo
	endif

cc now charges of the INDEX fragments stored in Z(1,...,INDEX)

cc calculate nzb,nzb3,nal and check
	NZB = 0
	NZB3 = 0
	do I=1,INDEX
	 NZB = NZB + Z(I)
	 if (Z(i).gt.2) NZB3=NZB3+Z(I)
	enddo
	if ((NZB.ne.ZB).or.(NZB3.ne.ZB3)) BINCON = .true. 

cc warnings and errors
	if (BINAC) then
	  write (*,*) ' No unambigous reconstruction possible for event ',ENUM
	endif
	if (BINCON) then
	  write (*,*) ' ERROR: INCONSISTENCY IN EVENT ',ENUM
	endif
cc ---------------
cc privat analysis
cc ---------------
	goto 1
c end loop over events

1000	close(3)
	write (*,*) IENUM,' events scanned.'
2000	format(i8,14i4)
2001	format(i8,19i4)
	end